- Joined
- Jun 6, 2003
Cooling performance depends very much on the surface of the HS, so take the time and examine my calculations below please.
The surface of an average cooler would be
surface of fins + surface of base
lets assume:
fin surface = 8 cm width * 5 cm height *2 (each fin two sides) * pcs of fins? Lets say 50 fins = 4000 cm2
base surface = 8 * 8 = 64 cm2
total surface = 4064 cm2
Ok lets say 0,5 m2.
But what if I would use copper wires instead of fins.
Lets say 0,5 mm diameter copper wire length 60 mm (6 cm)
The surface of each = 2 * 3,14 * 0,25 *60 = 94,2 mm2 (I omit the base and top of the wires)
How many wires would fit on this cooler? Assume that base of cooler is circular, say 50 mm diameter (5 cm a very small cooler)
The surface of this base would be = 3,14* (25mm *25mm ) = 1962,5 mm2
The surface of the base of each wire would be = 3,14 * (0,25mm *0,25mm) = 0,19625 mm2
So 1962,5 / 0,19625 = 10.000 wires
The surface of 1 wire was 94,2 mm2 * 10.000 = 942.000 mm2 = 0,942 m2
Almost double the surface in half the size ? Woww!!
Do you think my calculations are correct?
If so, did anybody seen such a cooler, (It would actually look like a brush.
If cooling performance mostly depends on the surface of the cooler than such a design would be a definite winner.
PS: I just calculated with 0,2 mm wire and got 2,35 m2 cooling surface 5 times more then an average HS.
The surface of an average cooler would be
surface of fins + surface of base
lets assume:
fin surface = 8 cm width * 5 cm height *2 (each fin two sides) * pcs of fins? Lets say 50 fins = 4000 cm2
base surface = 8 * 8 = 64 cm2
total surface = 4064 cm2
Ok lets say 0,5 m2.
But what if I would use copper wires instead of fins.
Lets say 0,5 mm diameter copper wire length 60 mm (6 cm)
The surface of each = 2 * 3,14 * 0,25 *60 = 94,2 mm2 (I omit the base and top of the wires)
How many wires would fit on this cooler? Assume that base of cooler is circular, say 50 mm diameter (5 cm a very small cooler)
The surface of this base would be = 3,14* (25mm *25mm ) = 1962,5 mm2
The surface of the base of each wire would be = 3,14 * (0,25mm *0,25mm) = 0,19625 mm2
So 1962,5 / 0,19625 = 10.000 wires
The surface of 1 wire was 94,2 mm2 * 10.000 = 942.000 mm2 = 0,942 m2
Almost double the surface in half the size ? Woww!!
Do you think my calculations are correct?
If so, did anybody seen such a cooler, (It would actually look like a brush.
If cooling performance mostly depends on the surface of the cooler than such a design would be a definite winner.
PS: I just calculated with 0,2 mm wire and got 2,35 m2 cooling surface 5 times more then an average HS.