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i have read this in another post about DDR 333 rams
can anybody explain it to me ?
can anybody explain it to me ?
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what is DDR 333 ?
- Thread starter .. AE 86 ..
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333 is 166 doubled sooo...... PC2700
266 is 133 doubled sooo..... PC2400
200 is 100 doubled sooo..... PC2100
so on and so on and so on
266 is 133 doubled sooo..... PC2400
200 is 100 doubled sooo..... PC2100
so on and so on and so on
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Small mistake hereLutaWicasa said:333 is 166 doubled sooo...... PC2700
266 is 133 doubled sooo..... PC2400
200 is 100 doubled sooo..... PC2100
so on and so on and so on
333 = 166 X 2= PC2700
300 = 150 X 2= PC2400
266 = 133 X 2= PC2100
200 = 100 X 2= PC1600
You will need a MoBo that has a 1/6 divider for 333 & 1/5 for 300 to have your PCI & AGP run within spec. Sometimes they will but it's never certain.
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No, big mistake. I need to engage my brain before my keyboard
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LutaWicasa - Have you heard anything about the KR7A - RAID having support for 1/5 & 1/6 dividers?
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sonny said:
Small mistake here
333 = 166 X 2= PC2700
300 = 150 X 2= PC2400
266 = 133 X 2= PC2100
200 = 100 X 2= PC1600
You will need a MoBo that has a 1/6 divider for 333 & 1/5 for 300 to have your PCI & AGP run within spec. Sometimes they will but it's never certain.
Small mistake here,
PC1600 (100 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 1600 MB/s available bandwidth.
PC2100 (133 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2128 MB/s available bandwidth.
PC2400 (150 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2400 MB/s available bandwidth.
PC2700 (166 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2656 MB/s available bandwidth.
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UnseenMenace said:
Small mistake here,
PC1600 (100 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 1600 MB/s available bandwidth.
PC2100 (133 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2128 MB/s available bandwidth.
PC2400 (150 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2400 MB/s available bandwidth.
PC2700 (166 MHz Operating Speed) x (2x Rising & Falling) x (64-bit Bus) / (8 bits per byte) = 2656 MB/s available bandwidth.
Tell me what the mistake was? I really don't see the diff? Yes, I need you to explain to me slooooooooooooooooooooooooooooowly. I thought my figures were right
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so far unseenmenace has explained it the best,
i was sitting there reading, hmmm how do they get from
333=166 x 2 to it equaling pc2700
then enseenmenace explained it and i was like wow i now understand.
i was sitting there reading, hmmm how do they get from
333=166 x 2 to it equaling pc2700
then enseenmenace explained it and i was like wow i now understand.
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sonny said:
Last anything I've been able to find out is 1/5 : fer shur 1/6 : a very strong probability. You can expect all the big boys to be utilizing the 1/6 with the emminent release of the Iwill XP333. Just a shame they hadda go with the Ali chipset.
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GREAT!!!!!!!! I'm taking delivery of it in a few days but don't have the DDR yet. They are taking forever to deliver my PC150 for my current MoBo
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K808 said:
the PC2700 will require the user to run a higher FSB to maximise the performance available with the memory, however this does not mean that your system will be able to run at the high FSB required as your cards and other hardware may hold you back
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sonny said:
You never actually got it wrong, however you did over simplify the calculations, and it was the sarcastic british sence of humour that was just pointing out that in the same manner as you did to 'LutaWicasa' who did not actually get the math 'wrong' but over simplified it
Perhaps my humor is abstract, however no offence or insult was meant by it
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He did actually make a small mistake but we are all here to help or confuse each otherUnseenMenace said:
Your humor is well understood, been seeing a lot of Jeremy Clarkson 
