- Joined
- Jun 1, 2014
No, a radiator with the fans off will still have a temperature differential with the atmosphere, therefore incurring an airflow through the radiator.
That's simple thermodynamics. Period. It's obvious you know nothing about how heat transfer actually occurs.
I understand the graphs. I also understand that a flatter graph will have a slope closer to zero, when you're saying a steeper graph has a slope closer to zero.
How about this, YOU go do some testing. You're the new kid on the block.
You're ignoring the fact that airflow through a radiator has diminishing returns. Real life doesn't ignore that fact.
Just because you have 4x the airflow through this given radiator doesn't mean you get 4x the cooling! THE GRAPH YOU POSTED SHOWS THIS.
You've got what, four experienced and respected members of the forum saying "you're wrong", but you don't realize it? Sad.
LOL, and still nothing to back it up. Post some evidence. I have already.
You'r saying no and just repeating what I posted now. In an enclosed environment the rad will warm the air to the same temp as the rad itself and cooling is zero. In an open environment the heat of the rad causes warm air to rise and induces an air flow. So what, the 480 rad still needs about 500 RPM to dissipate 200 Watts.
Deminishing returns applys at high RPM'S because radiator restriction (like all restriction) increases with speed. More RPM's are needed for the same airflow. That is what the graph shows.
That has nothing to do with at the effects at the lower end and nothing you have said contradicts the fact that a 120 rad at high speed is equal to a 480 rad at low speed. Its time to give it up because its getting pathetic.
A 480 rad that dissipates 200 watts at zero RPM and 10C delta ... I'll take one of those.
Last edited: