What Is The Best Way To Determine An Overclocked Processor Heat Output?

There are 2 methods I have heard of. One is similar to this:

morphling1 said:

You're right it's not math, but it it holds much better then linear increase in speed and heat output
skip 2400+
Lets take a look at 2600+
2133 MHz 1,65V 68.3W
Compared to 1800 MHz 2200+ that's 333MHz increase in frequency which like I said adds 3W
So 62.8+3=65.8 now here we also have increase in voltage so 65.8*1.65/1.6 = 67.85W so only 0.5 W off the correct mark
So if I'm of by lets say 5W at 2700MHz 2.2W that's nothing compared to 186W calculation right

Click to expand...

The other is:

Heat Output = Max. Thermal Power Dissipation x (Overclocked speed/stock speed) x [(Overclocked vCore/StockvCore)^2]

Which one is more accurate?

Esamating Processor Wattage

The best way to esimate a given processors heat output is to us this formula:
Power = C*Fclk*V^2
C=Powermax / (Fclknominal * Vnominal^2)
once C is found then
Power = C * Fclknew*Vnew^2
when Fclknew and Vnew are the new processor clock speed and voltage.

Example
60W chip, 1533MHz, 1.75V
C=60/(1533e6 * 1.75^2)=1.278e-8

now 1533 is 1800 and V=1.90
Power=1.278e-8 * 1800 *1.9^2 =83W
So you can see that a there is 38% more power for 10% more clock frequency.

This will give you a good approximate of its power consumption so you can plan your cooling approach.

Shane