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Yeah...to use actual physics variables, Current=I(Amperes), Voltage=V(Volts), Power=W(Watts), and I'll put resistance, which is R(Ohms). W=IV=(I^2)R since (V=IR) and W=IV=(V^2)/R since (I=V/R). Light bulb wattages given depend on where they are meant to be sold. In the US, the voltage you get from the wall is actually 115V, outside the US it's 220V. (correct me if I'm wrong) PSU's, however, have a switch to convert the resistance(?) to take 220V and keep it at it's max Power Rating.
What is this question for, may I ask? (Curiousity filled the cat)

Soy
 
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