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A real stumper!

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Old 08-11-03, 08:46 PM Thread Starter   #1
Frodo Baggins
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A real stumper!


Let n be any 5 digit number
Let m = n but with the middle digit chopped off

Find all n for which n/m is an integer

I've been staring at this problem for a bit and I can't figure it out for the life of me.

I think I know how to set it up though:
n is a 5 digit integer. The only way you'll be able to manipulate the center number is to compile the number manually.

Let n = 1000A + 100B + C

Where:

10 <= A <= 100
0 <= B <= 10
0 <= C <= 100

Therefore you are left to prove that:
Code:
               n = km
1000A + 100B + C = k(100A + C)
For any integer k

Where the heck do I go from here? Help me out guys!
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Old 08-11-03, 09:27 PM   #2
Oni
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Getting us to do your math homework, eh?

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Old 08-11-03, 10:23 PM Thread Starter   #3
Frodo Baggins
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it's not exactly homework (Though it is work and it's done at home)

summer problems I have trouble with
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Old 08-11-03, 10:47 PM   #4
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I love programming

So, how much will you pay me to write a program to brute-force the answer out?
JigPu

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Old 08-11-03, 10:49 PM Thread Starter   #5
Frodo Baggins
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nono, my friend (actually I hate his guts) solved this by hand

besides, even if you may generate the numbers, it's a different thing to generate the general formula for the problem
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Old 08-12-03, 09:41 PM Thread Starter   #6
Frodo Baggins
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*hack* *cough*

Oh hello there, did you come to visit my thread?
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Old 08-13-03, 06:37 AM   #7
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<blows whistle>

Personal Foul!

Unnecessary roughness on the admin!

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Gawd...the question hurt my brain...I will not even attempt to come up with a forumla now.......but maybe after you can get back in here, someone will have posted an answer for ya. =)

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