How do you find the number of digits in a number

besides dividing by 10 and keeping a counter? This is in c++.


//ah, int n = log10 + 1 works
//or ceil(log10)

You could sprintf it to an array in memory and count the size of the array. You could also use a switch statement to check the size, basically the number of digits is 1 if it's between 0 and 9, 2 if if it's between 10 and 99, etc.) You could also do it with logarithms, but calculating logs is slow, so it's not an efficient way to do it.