- Joined
- Jul 24, 2002
- Location
- Seattle, WA
According to some good calculations, it's about .5* C at the very most. Probably less. Really, it's been proven time and again - it doesn't matter. Route your tubing in the most convenient manner.The water carries the spent energy (heat) from the CPU to the rad where it (heat) is then transfered to the air. If your block is doing it's job, there should be quite a bit of heat transfered to the water. In turn if the rad/fan is doing its job most of that heat should be transfered to the ambient room.....
Let me dig up a link. But first, realize that just because the water in your loop heats up, the water is still pretty much the same temperature at every point in your loop. Your tubing can surely be noticably warmer, but is the tubing going into the CPU block cooler than the tubing coming out?Where has this been proven. When I am gaming for long periods of time, the exhaust from my rad fan is quite warm. I can actually feel that the hoses are warmer....
Also, warm air coming off of your radiators DOES mean that heat is being dissipated - you're right. But air has a much lower heat capacity than water (this is why watercooling does a better job) and a small temperature decrease in water will produce a comparitively larger temperature increase for the given volume of air it is dissipated into. So even though the air seems significantly warmer, it's not cooling the water to the same "felt" degree.
Here's the info you requested. The data is for a pump, but the equation can be reworked for a higher heat load.
So for a 100w heatload (which is significant) you'll see about .19* C on the other side of the waterblock. That makes it about .4* C if you halve the flowrate. As you can see, with a typical loop, getting a difference of more than .5*C is pretty tough, especially when you consider that some of the CPU's heat is dissipated through surrounding circuitry.How about we inject a little bit of science into the equation eh?
Let's assume we have a Danner Mag 3, being a 35W pump. In actuality the pump will draw a low less power, but let's run with 35W.
Let's assume that the pump dumps all 35W of its power as heat into the water as the water flows through the pump.
Water has a thermal capacity of 4186 J/kg°C. Water has a density of 1.00
Let's assume that the flow rates through the system is 2GPM, or 7.5LPM, which is fairly reasonable given that pump and a moderate-high restriction block, or two low-moderate restriction blocks, and a low-restriction radiator.
Per second, 7.5/60 = 0.125l, or 0.125kg of water flows through the pump, for a total thermal capacity of 4186 * 0.125 = ~523W/°C
Keeping that the pump dumps 35W of heat into the water, then the water will rise by 35/523 = 0.067°C as it flows through the pump.
So the difference between having the radiator before/after the pump is just 0.067°C
So there's the mathematical/physics way to disprove the misconception.
I don't see why people think two loops is best. It's twice the pump heat overall, and you won't be using your radiators as efficiently as you would in a single loop. It's also creates more clutter and doubles your chances of pump failure, plus you need to worry about the extra cost of another pump and the extra power draw on your system. The only gain is a small increase in flowrate due to lower restriction - likely not enough to offset the performance decrease from the factors mentioned above.2 Loops would work great. Again I was thinking CPU> Rad> Vid> Pump> Rad> Cpu
To the OP:
A single Black Ice XtremeII should work just fine. You could add another radiator, but the affects of having would likely be very little, if at all noticable. If it were me, I would reject having the second radiator on the grounds of the lack of performance increase, but would be even more strongly against the idea due to the hassle and inconvenience it would cause. Sometimes it's just a pain to add things like that to the loop. If there's one thing I've learned from watercooling over the last 3.5 years or so, it's KEEP IT SIMPLE.
Last edited: