Edit!: This calculation is oversimplified and will not get you "exact" temps. It also contains some errors. Please read post from Since87 and Doc to learn where the errors/deviations are.
The biggest errors are my optimistic efficency increase between interfacing a TEC with cooler (as most data are found for cooler on cpu die). I compensate with overly negative figures for TECs efficiency. Further down the posts you'll find a handy Excel spread sheet for TEC calcs, made by Since87.
Enjoy! /Paxmax
I going try to explain how to calculate approximate processortemps using a peltier(TEC).
The answer we can get from the calc is Tc, the temp of the coldside of the TEC. The actual processor temperature will be warmer due to thermal interface losses.
The TEC should be looked at as a heat pump. It MOVES heat from coldside to the hotside, if you have observed the polarity correct!
The processorheat will be moved and dumped on whatever is there to cool the hotside. If there isn't anything there to cool it, or the cooling is insufficient, then the TEC will burn up, usually when it reaches around 80 Celcius.
Besides dumping the moved processorheat to the hotside, it will also dump the heat from the power it requires to be able to MOVE the heat.
The TEC is not a magical device, it's a pump, it can't move more heat than input power. At best it moves about 90-95% of supplied power.
The calc I use is in three steps, like this:
Tdif =(1-(Ph/Pc))*Dmax
Th=Tamb+(C/W*(Win+Ph))
Tc =Th - Tdif
Tdif = Temperature difference between the hotside and the coldside, in Celsius
Ph =processorheat, in Watts
Pc = TEC cooling power, in Watts
Win =The power needed to operate TEC, to produce the Pc. Measured in Watts
Dmax = A sort of efficiency and "quality" measure of a TEC running on max without ANY heatload. The value is usually between 60 and 90.
Th =Temperature on hotside of TEC, in Celsius
Tc =temperature on coldside of TEC in Celcius
Tamb = Ambient temperature or room temp in Celsius
C/W = The efficiency of a cooling device.
The C/W value will depend on many factors. Some are: what kind of paste is used, the contact area, clamping pressure, flatness/roughness of surfaces and such.
A really good aircooler today will yield a C/W rating under 0.30 when used with overclockers.com processor simulation device.
When the same aircooled heatsink is used with a TEC the C/W value will be better (for the heatsink/TEC interface) due to larger contact area.
To pass all heat from the processor through the small footprint of it, is like passing high current through a thin wire, there will be high resistance and losses involved.
I don't know exactly how much better so I'm doing a bit of guesswork. The footprint of a TEC is around 14 times bigger than a processor, that doesn't of coz mean it's 14 times better though.
The aircooler efficiency might double or something due to the better distribution of heat and lower heat per contact area.
Any waterblock should also yield better C/W with a peltier than on a processordie.
An example with TEC then....
Lets say we have 70W heat from processor, and we use a 226W TEC. Ambient temp =25 celcius
The TEC's data is: Dmax=67c, Pc=226W, Vmax=15.2, Imax=24
To get the 226W Pc cooling power, we have to input 15.2 volts * 24 ampere = 365 Watts
We cool it with an aircooler Swifttec MCX 462 it has a C/W rating of 0,26. I will be calculating with a C/W of only half of it, since the heatsink will be working more effciently with a large heatsource.
Tdif =(1-(70/226))*67 = 46,25 C Tdif Temperature difference between Coldside and the hotside
Th = 25 + (0.13* (365 + 70)) = 81,5 C at the hotside !!!! Thats a hot heatsink, and that peltier is on the verge to destroy itself.
Tc = 81,5 - 46,25 = 35,25 Celcius!!
Ooops... The cold side of the TEC will be 35,25 cecius, thats not exactly "cold". Not what you expect when you use a good TEC.
The 226W TEC / aircooled heatsink solution isn't going work too well at the TECs maximum rating since the heatsink can't handle the thermal load.
If we run the TEC at 12 volts(80% of Vmax) instead of Vmax we will run the TEC more efficiently.
226W TEC @ 12 volt draws approx 19 A (instead of 24 A)
Pin will be 12 * 19 = 227 W. As a result of lowering input power the Pc will drop to about 90% of input power .9 * 227 =204 W
Doing the calculation again then:
Tdif =(1-(70/204))*67 = 44 celcius (we lost 2 C in temperature difference)
Th = 25+(0.13*(227+70)) = 63,6 C (we got 18 C colder at the hotside)
Tc =63,6 - 44 = 19,6 Celcius on the coldplate
19.6 is the calculated MAX temperature your TEC's coldside will be during full 70W heatload if we ignore a few losses here and there.
It's only 5 C below ambient, thats much better than what you'd get with the aircooled heatsink alone!
With the heatsink alone you'd get 25C + (0.26C/W * 70W ) = 43 C
A cool feature is that you can check theese results with an test done by overclockers.com see http://www.overclockers.com/articles646/
Another cool thing is, I have been using this formula for 2 years.
The C/W value is a true guesswork and it will vary from cooler to cooler, the other values can easily be calculated. Just exchange your numbers with mine in the calculation to test your config.
Remember that the Cooling power(Pc) drops when you run your TEC on other voltage than Vmax. Remember to also calculate new Win(power supplied) for the TEC when you operate it on other voltage than Vmax.
If you drop Volts by 80% you have to recalculate the Amperes by using Ohm's Law.
U = voltage in volts, I = Current in Amperes, R = resistance in Ohms.
Rules are: U/I=R and U/R=I and R*I=U
Also the power. U*I=P in watts
The problem with using TEC isn't to get it cold, it is to provide enough cooling for the hotside.
Mating TEC's with watercooling is necessary to get substancially below ambient temp, or use a puny processor!!
Good speed = Overclocked speed
And please flame me if needed, and prove me wrong, cuz after all this is all just theory.....
/Paxmax
The biggest errors are my optimistic efficency increase between interfacing a TEC with cooler (as most data are found for cooler on cpu die). I compensate with overly negative figures for TECs efficiency. Further down the posts you'll find a handy Excel spread sheet for TEC calcs, made by Since87.
Enjoy! /Paxmax
I going try to explain how to calculate approximate processortemps using a peltier(TEC).
The answer we can get from the calc is Tc, the temp of the coldside of the TEC. The actual processor temperature will be warmer due to thermal interface losses.
The TEC should be looked at as a heat pump. It MOVES heat from coldside to the hotside, if you have observed the polarity correct!
The processorheat will be moved and dumped on whatever is there to cool the hotside. If there isn't anything there to cool it, or the cooling is insufficient, then the TEC will burn up, usually when it reaches around 80 Celcius.
Besides dumping the moved processorheat to the hotside, it will also dump the heat from the power it requires to be able to MOVE the heat.
The TEC is not a magical device, it's a pump, it can't move more heat than input power. At best it moves about 90-95% of supplied power.
The calc I use is in three steps, like this:
Tdif =(1-(Ph/Pc))*Dmax
Th=Tamb+(C/W*(Win+Ph))
Tc =Th - Tdif
Tdif = Temperature difference between the hotside and the coldside, in Celsius
Ph =processorheat, in Watts
Pc = TEC cooling power, in Watts
Win =The power needed to operate TEC, to produce the Pc. Measured in Watts
Dmax = A sort of efficiency and "quality" measure of a TEC running on max without ANY heatload. The value is usually between 60 and 90.
Th =Temperature on hotside of TEC, in Celsius
Tc =temperature on coldside of TEC in Celcius
Tamb = Ambient temperature or room temp in Celsius
C/W = The efficiency of a cooling device.
The C/W value will depend on many factors. Some are: what kind of paste is used, the contact area, clamping pressure, flatness/roughness of surfaces and such.
A really good aircooler today will yield a C/W rating under 0.30 when used with overclockers.com processor simulation device.
When the same aircooled heatsink is used with a TEC the C/W value will be better (for the heatsink/TEC interface) due to larger contact area.
To pass all heat from the processor through the small footprint of it, is like passing high current through a thin wire, there will be high resistance and losses involved.
I don't know exactly how much better so I'm doing a bit of guesswork. The footprint of a TEC is around 14 times bigger than a processor, that doesn't of coz mean it's 14 times better though.
The aircooler efficiency might double or something due to the better distribution of heat and lower heat per contact area.
Any waterblock should also yield better C/W with a peltier than on a processordie.
An example with TEC then....
Lets say we have 70W heat from processor, and we use a 226W TEC. Ambient temp =25 celcius
The TEC's data is: Dmax=67c, Pc=226W, Vmax=15.2, Imax=24
To get the 226W Pc cooling power, we have to input 15.2 volts * 24 ampere = 365 Watts
We cool it with an aircooler Swifttec MCX 462 it has a C/W rating of 0,26. I will be calculating with a C/W of only half of it, since the heatsink will be working more effciently with a large heatsource.
Tdif =(1-(70/226))*67 = 46,25 C Tdif Temperature difference between Coldside and the hotside
Th = 25 + (0.13* (365 + 70)) = 81,5 C at the hotside !!!! Thats a hot heatsink, and that peltier is on the verge to destroy itself.
Tc = 81,5 - 46,25 = 35,25 Celcius!!
Ooops... The cold side of the TEC will be 35,25 cecius, thats not exactly "cold". Not what you expect when you use a good TEC.
The 226W TEC / aircooled heatsink solution isn't going work too well at the TECs maximum rating since the heatsink can't handle the thermal load.
If we run the TEC at 12 volts(80% of Vmax) instead of Vmax we will run the TEC more efficiently.
226W TEC @ 12 volt draws approx 19 A (instead of 24 A)
Pin will be 12 * 19 = 227 W. As a result of lowering input power the Pc will drop to about 90% of input power .9 * 227 =204 W
Doing the calculation again then:
Tdif =(1-(70/204))*67 = 44 celcius (we lost 2 C in temperature difference)
Th = 25+(0.13*(227+70)) = 63,6 C (we got 18 C colder at the hotside)
Tc =63,6 - 44 = 19,6 Celcius on the coldplate
19.6 is the calculated MAX temperature your TEC's coldside will be during full 70W heatload if we ignore a few losses here and there.
It's only 5 C below ambient, thats much better than what you'd get with the aircooled heatsink alone!
With the heatsink alone you'd get 25C + (0.26C/W * 70W ) = 43 C
A cool feature is that you can check theese results with an test done by overclockers.com see http://www.overclockers.com/articles646/
Another cool thing is, I have been using this formula for 2 years.
The C/W value is a true guesswork and it will vary from cooler to cooler, the other values can easily be calculated. Just exchange your numbers with mine in the calculation to test your config.
Remember that the Cooling power(Pc) drops when you run your TEC on other voltage than Vmax. Remember to also calculate new Win(power supplied) for the TEC when you operate it on other voltage than Vmax.
If you drop Volts by 80% you have to recalculate the Amperes by using Ohm's Law.
U = voltage in volts, I = Current in Amperes, R = resistance in Ohms.
Rules are: U/I=R and U/R=I and R*I=U
Also the power. U*I=P in watts
The problem with using TEC isn't to get it cold, it is to provide enough cooling for the hotside.
Mating TEC's with watercooling is necessary to get substancially below ambient temp, or use a puny processor!!
Good speed = Overclocked speed
And please flame me if needed, and prove me wrong, cuz after all this is all just theory.....
/Paxmax
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