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The math for CPU Watts...

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engjohn

Senior Member
Joined
Dec 18, 2000
Location
SoCal
I have used two ways. One is this equation..

Hoc=Hdef(Vnew/Vdef)^2(Snew/Sdef).
Hdef =the defaut heat of your CPU which I'll guess is 15-16Watts more precise can be found on the Intel spec sheet for it.
Vnew is your new voltage,
Vdef is default voltage, and that "^2" is too the power of 2 or just square the answer in those brackets.
Snew is your new CPU speed (1035),
Sdef is your CPU's default speed (633).

and I have used Radiate.exe from

Now, which is right??

Radiate shows 41.8 Watts for a cele 633 @ 1030 @ 1.95
and if you do the math is shows 34.2 Watts for the same CPU.

Is the math wrong, or is Radiate wrong? Or is there a better way???
 

wild_andy_c

NAKED Overclockers Unite! Senior
Joined
Dec 17, 2000
Location
Milton Keynes UK
Given the mitigating circumstances of dissipation, the data given by radiate may have some meaning.

Be interesting to do a reverse alog to find out. Someone try boiling 10cc of water on a processor to work out the power output!!!!