I have used two ways. One is this equation..
Hoc=Hdef(Vnew/Vdef)^2(Snew/Sdef).
Hdef =the defaut heat of your CPU which I'll guess is 15-16Watts more precise can be found on the Intel spec sheet for it.
Vnew is your new voltage,
Vdef is default voltage, and that "^2" is too the power of 2 or just square the answer in those brackets.
Snew is your new CPU speed (1035),
Sdef is your CPU's default speed (633).
and I have used Radiate.exe from
Now, which is right??
Radiate shows 41.8 Watts for a cele 633 @ 1030 @ 1.95
and if you do the math is shows 34.2 Watts for the same CPU.
Is the math wrong, or is Radiate wrong? Or is there a better way???
Hoc=Hdef(Vnew/Vdef)^2(Snew/Sdef).
Hdef =the defaut heat of your CPU which I'll guess is 15-16Watts more precise can be found on the Intel spec sheet for it.
Vnew is your new voltage,
Vdef is default voltage, and that "^2" is too the power of 2 or just square the answer in those brackets.
Snew is your new CPU speed (1035),
Sdef is your CPU's default speed (633).
and I have used Radiate.exe from
Now, which is right??
Radiate shows 41.8 Watts for a cele 633 @ 1030 @ 1.95
and if you do the math is shows 34.2 Watts for the same CPU.
Is the math wrong, or is Radiate wrong? Or is there a better way???