- Joined
- Dec 10, 2004
- Location
- The CircuitCity FireDog House
here is a summation of the information from the thread i started here.
http://www.ocforums.com/showthread.php?t=390731&page=2&pp=30
The freezing capacity of freezers is measured in kilograms/24 hours. This indicates the weight of fresh food that the freezer can freeze from room temperature down to -18°C in 24 hours.
1 calorie = the amount of energy required to heat 1 gram of water 1 degree celsius.
according to http://en.wikipedia.org/wiki/Heat_of_fusion, the heat of fusion of water is 79.72 calories per gram, that is, it takes 79.72 calories to melt one gram of ice. so if we have 860 grams of ice, it would take
860g x 79.72cal/g = 68559.2 cal = 68.56 kcal to melt the ice, PLUS
860g x 38 degrees = 32680 cal = 32.68 kcal to raise the water to room temp, EQUALS
101.24 kcal
so the freezer is sucking out 101.24 kilocalories every 24 hours.
according to http://www.onlineconversion.com/power.htm, 135watts = 116 kilocalories/hour, so your processor outputs 2784 kilocalories/24hr.
processor = 2784 kilocalories/24hr
minifreezer = -101.24 kilocalories/24hr
so 101.24 divded by .86 is 117.72
so 1Kg/24 hours equals -117.72 kilocalories
so the processor with 135watts puts out just shy of 2800 Kilocalories
so 2800 divided by 117.72 is 23.785
so you need a freezer that cools at least 24Kg/24Hours just to cover the processor heat.
not including the videocard and rest of system heat.
http://www.ocforums.com/showthread.php?t=390731&page=2&pp=30
The freezing capacity of freezers is measured in kilograms/24 hours. This indicates the weight of fresh food that the freezer can freeze from room temperature down to -18°C in 24 hours.
1 calorie = the amount of energy required to heat 1 gram of water 1 degree celsius.
according to http://en.wikipedia.org/wiki/Heat_of_fusion, the heat of fusion of water is 79.72 calories per gram, that is, it takes 79.72 calories to melt one gram of ice. so if we have 860 grams of ice, it would take
860g x 79.72cal/g = 68559.2 cal = 68.56 kcal to melt the ice, PLUS
860g x 38 degrees = 32680 cal = 32.68 kcal to raise the water to room temp, EQUALS
101.24 kcal
so the freezer is sucking out 101.24 kilocalories every 24 hours.
according to http://www.onlineconversion.com/power.htm, 135watts = 116 kilocalories/hour, so your processor outputs 2784 kilocalories/24hr.
processor = 2784 kilocalories/24hr
minifreezer = -101.24 kilocalories/24hr
so 101.24 divded by .86 is 117.72
so 1Kg/24 hours equals -117.72 kilocalories
so the processor with 135watts puts out just shy of 2800 Kilocalories
so 2800 divided by 117.72 is 23.785
so you need a freezer that cools at least 24Kg/24Hours just to cover the processor heat.
not including the videocard and rest of system heat.