New at this...Need a little help
I have been thinking about getting a TEC unit, but I think I have to get a rather big one to cool my Prescott (478) 2,8@3,5Ghz down. 226Watt TEC I think will do the trick.
Watt = 78amps * 1,56volts = 121,68watts MAX!!
Watt = 40amps * 1,56volts = 62,4watts idle max.
(1-(121,68/226))*67=Delta T= 30,9267
Cold side is 30,9267C cooler then the hot side.
(1-(62,4/226))*67=Delta T= 48,5009
Cold side is 48,5009C cooler then the hot side.
My 2,8@3,5 (1,56volts) is generating around 62C of heat under load and around 50C idle.
Maybe I should get a bigger TEC unit.......? Or what do you think?
I have been thinking about getting a TEC unit, but I think I have to get a rather big one to cool my Prescott (478) 2,8@3,5Ghz down. 226Watt TEC I think will do the trick.
Watt = 78amps * 1,56volts = 121,68watts MAX!!
Watt = 40amps * 1,56volts = 62,4watts idle max.
eweast said:Delta T = (1 - (Heat Load/Max Cooling Power)) * Max Temp Difference
*) Delta T = The actual difference in temperature between the hot-side and the cold-side that you should experience in the real world.
*) Heat Load = The heat generated (in this case) by the processor measured in watts.
*) Max Cooling Power = Maximum TEC rating in watts. (e.g. a 221-watt TEC or a 80-watt TEC)
*) Max temp = TEC’s maximum temperature rating in degrees C (theoretical Delta T, a.k.a. Delta T max).
[Originally written 2/9/03]
(1-(121,68/226))*67=Delta T= 30,9267
Cold side is 30,9267C cooler then the hot side.
(1-(62,4/226))*67=Delta T= 48,5009
Cold side is 48,5009C cooler then the hot side.
My 2,8@3,5 (1,56volts) is generating around 62C of heat under load and around 50C idle.
Maybe I should get a bigger TEC unit.......? Or what do you think?
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